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Restoration of Lost Corners by Proportionate Measurement
 
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  Section 2 - Offset of Traverse and True Parallel - Try It

 
Compute offset from traverse point to parallel of latitude. Latitude must be between 25 and 75 N.
Latitude of True Parallel (DD.mmss); Example: 45° 34’ 30” would be entered as 45.3430
Total distance along traverse (in Chains):
Forward bearing at beginning point of traverse (DD.mmss) No alpha characters; Example: N. 89 15 W. would be entered as 89.15:
Offset from traverse to true parallel of latitude (in Chains):
      
Your retracement begins at the original township corner of Tps. 3 and 4 North, Rs. 7 and 8 west, where you have established a true bearing by solar observations. The latitude of this cor. is 45° 34' 30" N. You traverse 4 miles westerly before you find an original corner and determine the intermediate corners to be lost. You now need to reestablish the corner of sections 2 and 3 only. Your random traverse yields the following data.

Inverse from Tp. Cor. to cor. of secs. 4 and 5:

  • S. 88° 42’ W. 321.07

Inverse between tp. cor. and temp cor. of secs. 2 and 3:

  • N. 89° 46’ W 160.12

The original survey reports the following from the tp. cor.:

  • West 40.00 ¼ cor. sec. 1 only
  • West 40.00 cor. of secs. 1 and 2 only
  • West 40.00 ¼ cor. sec 2 only
  • West 40.00 cor. of secs. 2 and 3 only
  • West 40.00 ¼ cor. secs. 3 only
  • West 40.00 cor. of secs. 3 and 4 only
  • West 40.00 ¼ cor. sec. 4 only.
  • West 40.00 cor. of secs. 4 and 5 only

The lost cor. of secs. 2 and 3 would be reestablished by single proportionate measurement. However, if you fail to account for curvature of the township line, how far off will your reestablished corner be?

Using the curvature calculator you can determine how much curvature must be factored into your final corner position. Using the single proportion formula, determine the position of the lost corner. Do you remember the formula?

retracement/record x record or 321.07/320.00 x 160 = 160.535

The proportionate position of the cor. of secs. 2 and 3 would be located:
S. 88° 42’ W. 160.535 from the tp. cor.

But, you’re not finished yet. What about curvature? You need to apply this to your single proportion answer to arrive at the final position for the corner.

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